Question

calculate the pressure exerted by a boy weighting 1000N standing on a heel of area 1m²​

Answer 1

GIVEN :-

• Force = 1000N
• Area of contact = 1 m².

TO FIND :-

• The pressure.

SOLUTION :-

$\implies \boxed{ \boxed{ \red{ \bf \: pressure \: (p) = \dfrac{thrust(F)}{Area(A)} }}}$

➠ Now substitute the values ,

$\to \rm \: \dfrac{1000 \: N}{1 \: m^{2} } \\ \\ \to \rm \: 1000 \: N \: m ^{ - 2} \\ \\ \red{ \to \bf \: pressure \:(p) = 1000 \: pascal}$

Hence the pressure is 1000 Pascal.

EXTRA INFORMATION :-

➠ Pressure :- The perpendicular force (thrust) acting per unit area of the surface .

➠ S.I unit of pressure is Pascal

➠ S.I unit of force is Newton (N).

➠ S.I unit of area is m².

➠ factors on which pressure depends .

⭑Amount of force applied.

⭑ Area over which force acts.

➠ Pressure is directly proportional to thrust acting on surface .

➠ Pressure inversely proportional to area of surface .

➠ pressure is directly proportional to depth

Answer 2

Answer:

EXTRA INFORMATION :-

➠ Pressure :- The perpendicular force (thrust) acting per unit area of the surface .

➠ S.I unit of pressure is Pascal

➠ S.I unit of force is Newton (N).

➠ S.I unit of area is m².

➠ factors on which pressure depends .

⭑Amount of force applied.

⭑ Area over which force acts.

➠ Pressure is directly proportional to thrust acting on surface .

➠ Pressure inversely proportional to area of surface .

➠ pressure is directly proportional to depth