Question

Calculate the pressure exerted by a brick, which applies a force of 2.5 N, when (a) it is placed upright on the soil, (b) when it is placed on it's widest base. The dimensions of the brik are 25 cm * 10cm * 5cm.

Please give right answer I spend my all points.​

Answer 1

$\fbox{\fbox{\mathfrak{\large{Solution:-}}}}$

(a). When the brik is placed up right:

Area in contact with soil

$= \frac{10}{100} m \times \frac{5}{100} m \times 0.005 {m}^{2}$

therefore Pressure exerted

$= \frac{f}{a} = \frac{2.5n}{0.005 {m}^{2} } = 500pa$

(b). When the brick is placed on it's widest base:

Area in contact with soil

$= 25cm \: \times \: 10cm$

$= \frac{25}{100} m \times \frac{10}{100} m = 0.025 {m}^{2}$

therefore Pressure exerted

$= \frac{f}{a} = \frac{2.5n}{0.25 {m}^{2} } = 100pa$

Answer 2

Explanation:

Answer refer in Attachment

Thank you