Question

calculate the pressure exerted by a brick which applies a force of 2.5N when it is placed upright on soil and dimensions are 25cm *10cm*5cm

Answer 1

$\underline{\textsf{\textbf{ \: Given \: Information : }}}$

• Force applied by brick (F) = 2.5 N

• Length of Brick = 25 cm

• Breadth of brick = 10 cm

• Height of brick = 5 cm

$\underline{\textsf{\textbf{ \: To \: Calculate : }}}$

• Pressure exerted by the brick (P).

$\underline{\textsf{\textbf{ \: Calculation : }}}$

We know that,

$\bigstar \: \boxed{\sf {P = \dfrac{F}{A} }}$

• P = Pressure
• F = Force
• A = Area

We need to calculate the area first. When the brick is placed upright on soil, its length becomes 10 cm and breadth becomes 5 cm. So, when brick is placed upright:

• Length = 10 cm
• Breadth = 5 cm

★ Area = Length × Breadth

Substitute the value of length and breadth.

→ Area = 10 cm × 5 cm

→ Area = 50 cm² ⇒ 0.005 m²

We changed cm² to m² because we'll be calculating pressure in its SI unit, that is Pa. And Pa = N/m², so we need to convert cm² to m².

Now, substitute all the values in the formula of pressure.

$\bigstar \: \boxed{\sf {P = \dfrac{F}{A} }}$

$\longrightarrow \sf { P = \dfrac{2.5 \: N}{0.005 \: m^2} }$

$\longrightarrow \sf { P = \dfrac{25 \times 1000 \: N}{5 \times 10 \: m^2} }$

$\longrightarrow \sf { P = \dfrac{25 \times 100 \: N}{5 \: m^2} }$

$\longrightarrow \sf { P = 5 \times 100 N/m^2 }$

$\longrightarrow \sf { P = 500 N/m^2}$

$\longrightarrow \sf \red { P = 500 \: Pa}$

Therefore, the pressure exerted by a brick which applies a force of 2.5N when it is placed upright on soil is 500 Pa.

Answer 2

Answer:

500 Pa

Explanation:

Make the other one brainliest because he gave its explaination