Calculate the pressure exerted by a brick, which applies a force of 2.5 N, when(a) It is placed upright on the soil (b) When it is placed on its widest baseThe length, breadth and height of the brick are 25cm, 10cm & 5 cm respectively
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Answered by
307
since pressure=Force/Area
when it is placed upright its length and breadth will be 10 & 5 respectively
so area=10*5=50cm2=
0.005m2
Pressure=2.5N/0.005m2
=500N m-2
in case b it is placed on widest base i.e. 25cm
so area =25*10=2500cm2
=0.25m2
Pressure=2.5/0.25=10N m-2
when it is placed upright its length and breadth will be 10 & 5 respectively
so area=10*5=50cm2=
0.005m2
Pressure=2.5N/0.005m2
=500N m-2
in case b it is placed on widest base i.e. 25cm
so area =25*10=2500cm2
=0.25m2
Pressure=2.5/0.25=10N m-2
Answered by
15
Given:
Force = 2.5N
Length = 25cm
Breadth = 10cm
Height = 5cm
To find:
(a) Pressure when it is placed upright on the soil.
(b) Pressure when it is placed on its widest base.
Solution:
a) Pressure=Force/Area
Area = 10*5 = 50cm²
= 0.005m²
Pressure = 2.5N/0.005m²
= 500 N/m²
Hence, the pressure when it is placed upright on the soil is 500N/m².
b) Pressure=Force/Area
Area = 25*10 = 2500cm²
=0.25m2
Pressure = 2.5/0.25
= 10 N/m²
Hence, the pressure when it is placed on its widest base is 10 N/m².
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