Question

calculate the pressure exerted by a column of mercury of height 0.5 m . density of mercury is 13600kg/m3 and acceleration due to gravity is 10m/s2

Answer 1

Answer:

$h = 0.5 \: m$

$d = 13600 \: kg \: {m}^{ - 3}$

$g = 10 \: m {s}^{ - 2}$

Pressure exerted by a column = hdg

$p = 0.5 \times 13600 \times 10$

$p = 68000 \:$

Since unit for pressure = N m^-2,

$p = 68000 \: n {m}^{ - 2}$

Or,

$p = 6.8 \times {10}^{4} n {m}^{ - 2}$

Note: Please ignore the unit above because somehow you can't capitalize words so consider it as Nm^-2, not as nm^-2.

Thank you