Question

calculate the pressure exerted by a cubical box on the floor in 3D different ways. dimension of box 50*10*30 and force is 25 newton

Answer 1

As we know that the pressure on surface is equal to the force acting per unit area :
==============================>>>>>>

So, here dimensions of the surface is given: 50× 10 × 30

so ,
it is a cuboid so its area will be.

A= 2 (lb+bh+hl)

A = 2 (50×10+10×30+30×50)

A =2 (500+300+1500)

A= 2 (2300)

A=4600 m^2

Now force is given 25 N

so, Pressure = F/A

=25/4600

=1/184 pascal

=0.00543 pascal ,pressure will be exerted.
☺☺☺