Calculate the pressure exerted by a cubical box on the floor in 3 different ways. The dimensions of box are as follows: length=50 cm, breath=10 cm, height=30 cm find the answer
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The cubical box exerts pressure on the floor when it is placed on either of its faces.
A cubical has a pair of three faces thus it can exert pressure in three different ways.
Pressure = Force / Area
Let pressure be P and Force be F.
Area of face 1 = (0.5 × 0.3) = 0.15 m²
P₁ = (F / 0.15) N/M²
Area of face 2 = (0.5 × 0.1) = 0.05 m²
P₂= (F / 0.05 ) N/M²
Area of face 3 = (0.1 × 0.3) = 0.03 m²
P₃= (F / 0.03) N/M²
We should take note that the force is constant and only the pressure varies with area.
A cubical has a pair of three faces thus it can exert pressure in three different ways.
Pressure = Force / Area
Let pressure be P and Force be F.
Area of face 1 = (0.5 × 0.3) = 0.15 m²
P₁ = (F / 0.15) N/M²
Area of face 2 = (0.5 × 0.1) = 0.05 m²
P₂= (F / 0.05 ) N/M²
Area of face 3 = (0.1 × 0.3) = 0.03 m²
P₃= (F / 0.03) N/M²
We should take note that the force is constant and only the pressure varies with area.
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Answer:
Explanation:
The cubical box exerts pressure on the floor when it is placed on either of its faces.
A cubical has a pair of three faces thus it can exert pressure in three different ways.
Pressure = Force / Area
Let pressure be P and Force be F.
Area of face 1 = (0.5 × 0.3) = 0.15 m²
P₁ = (F / 0.15) N/M²
Area of face 2 = (0.5 × 0.1) = 0.05 m²
P₂= (F / 0.05 ) N/M²
Area of face 3 = (0.1 × 0.3) = 0.03 m²
P₃= (F / 0.03) N/M²
We should take note that the force is constant and only the pressure varies with area.
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