Science, asked by parth7241, 1 year ago

calculate the pressure exerted by bricks of dimension 20 cm and 25 cm and force applied is 20N

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Answered by vibhamk923
0

Dimensions of brick= 20*25

Area of brick(A)= 500cm²

Force exerted by brick(F)= 20 N

Pressure= \frac{F}{A}= \frac{500}{20}= 25N/cm²


parth7241: galt hai
MathRockers: dimension of bricks is 20×25 cm therefore area is 500cm^2 or 1/20 m^2 and applied force is 20 N so pressure = F/A = 400N/m^2
vibhamk923: Note: the unit in my answer is N/cm^2
vibhamk923: so it is right in that sense
parth7241: tab bhi galt hai
parth7241: pahele cm ko m mi convert karna hoga as p=n/m2
parth7241: m sq
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