Question

Calculate the pressure exerted by cubical block placed over the surface.
m = 50kg and
side length = 5cm​

Answer 1

Answer:

1.96× 10⁵ Pa

Explanation:

$p = \frac{f}{a} \\ f = mg \\ \\ l = 5 \times {10}^{ - 2} m \\ a = {l}^{2} = 25 \times {10}^{ - 4} \\ \\ p = \frac{50 \times 9.8}{25 \times {10}^{ - 4} } \\ \\ = 19.6 \times {10}^{4} \\ \\ p = 1.96 \times {10}^{5} pa$