Question

calculate the pressure exerted by one mole of c2h6 behaving as an ideal gas and van del waals gas 273.414 k in 22.414 l (a=4.562, b=0.0638)​

Answer 1

Solution

According to Van der Waals equation of state for 1 mole of a gas

$(p + \frac{a}{ {v}^{2} } ) \: v = 0$

Since the volume occupied by gas

molecules is negligible, i.e.,

b = 0

therefore

$(p + \frac{a}{ {v}^{2} } ) \: v = RT$

$p = \frac{rt}{ { {v}^{2} } } - \frac{a}{ {v}^{2} }$