calculate the pressure exerted by the brick, which applies a force of 2.5N, when
i) it is placed upright in soil
ii)when it placed on its widest base
the dimensions of the brick are 25cm * 10 cm * 5 cm
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The applied Force is 2.5N
Dimensions of the brick is 25cm*10cm*5cm
We know Pressure=Force/Area
When it is placed upright=dimensions are 10cm*5cm
Area will be 50 square cm
In square metres=0.005 square metres.
Therefore,Pressure=2.5/0.005
Pressure=500Pa
When it's placed on the widest base
Dimensions are 25cm*10cm
Area of the base will be 250cm
Therefore,Pressure=2.5/0.025
Pressure=100 Pa
Dimensions of the brick is 25cm*10cm*5cm
We know Pressure=Force/Area
When it is placed upright=dimensions are 10cm*5cm
Area will be 50 square cm
In square metres=0.005 square metres.
Therefore,Pressure=2.5/0.005
Pressure=500Pa
When it's placed on the widest base
Dimensions are 25cm*10cm
Area of the base will be 250cm
Therefore,Pressure=2.5/0.025
Pressure=100 Pa
Komalalit14:
ji
multiply 10 into 5 why didn't we multiply 25 into 10 raise a very much confused in any confusion please help me in this
As the dimensions of the base will differ when u place it differently.
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