Question

Calculate the pressure exerted by water at the bottom of a beaker. The depth of water is 45cm. [Taken g = 10 m/s ^ 2 density of water=10^{3}kg/m^{3}]​

Answer 1

Answer:

pressur at the bottom of beaker =p=?

hight of water in beacker =h=40cm

h=0.4m

density of water = p

=1000kgm exeleration due to gravity = g=9.8 ms

p=0.4x1000x9.8

=3920pa