Question

Calculate the pressure exerted by5.12 grams of chlorine gas in a 850. mL sealed flask at 27.0C

Answer 1

Answer:

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Explanation:

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Answer 2

Given:

w = 5.12 gm

V = 850 ml = 0.85 L

T = 27 °C = 27 + 273 = 300 K

To Find:

The pressure exerted by Chlorine gas.

Calculation:

- 1 mole of chlorine gas is Cl2 = 2 × 35.5 = 71 gm

- The no of moles of Chlorine gas = 5.12/71 = 0.072 moles

- Using the ideal gas equation, we get:

P = nRT/V

⇒ P = (0.072 × 0.082 × 300) / 0.85

⇒ P = 1.77 / 0.85

⇒ P = 2.08 atm (approx)

- So, the pressure exerted by chlorine gas is approximately 2.08 atm.