Calculate the pressure exerted on a floor by a boy whose mass is 45kg and area of sole is 300cm^2
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Normal force exerted by the boy=mg=45 x 10=450N
Area=300cm^2=0.03cm^2
Pressure=force / area=450/300=1.5 pascals
mehtavaishali1007:
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Answered by
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Pressure= Force / Area
Given Area= 300cm^2 = 0.03 M^2
Force = 45 Kg = 45 X 10 = 450 Newton
Pressure = 450/0.03 = 13.5 Nm^2 or 13.5 Pascal
Given Area= 300cm^2 = 0.03 M^2
Force = 45 Kg = 45 X 10 = 450 Newton
Pressure = 450/0.03 = 13.5 Nm^2 or 13.5 Pascal
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