calculate the pressure exerted on an a surface of 0.5 m square by a thrust of 100 KGF
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Answered by
3
Pressure = thrust/area
Area=0.5*0.5=0.25m^2
Thrust=100N
Pressure =100/0.25=400Nm^-2
Thus the pressure exerted is 400Nm^-2.
Area=0.5*0.5=0.25m^2
Thrust=100N
Pressure =100/0.25=400Nm^-2
Thus the pressure exerted is 400Nm^-2.
abhisheksinha2:
200 Pascle ans hai
0.5 area hai?
agar haan to 200pa hi answer hai
ok
Answered by
7
P=Thrust÷area
=100÷0.5
=200 Pa
=100÷0.5
=200 Pa
plz explain karo
pressure=thrust÷area
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