Physics, asked by Anushanth306, 8 months ago

Calculate the pressure exerted on the floor by a boy standing on both feet if the weight
of the boy is 40000 N. The area of contact of each shoe is 6 cmX25cm.

Answers

Answered by ramdevsad66
0

Answer:

5000000000 I s the answer of this question

Answered by mail2rheaagr40
0

Answer:

13.33kNm2or 13.33kPa.

Explanation:

For the given question we can use the formula, F=mg where F is the gravitational force, m is the mass of the body and g is the acceleration due to gravity.

We know that, P=FA where P is the pressure exerted by a body, F is the force acting on the body and A is the area where the force acts.

We are given that a boy is standing on both feet on the floor. The weight of the boy is 40kg and the area of contact of each shoe is 6 cm by 25 cm .

We know that 1kgwt=10N

Hence, 40kg wt can be converted to 40×10=400N

The area of contact of each shoe=6cm×25cm=(6100×25100)m2=151000m2

Hence, total area of contact is (151000×2)m2=3100m2

We know that

P=FA

⇒P=4003/100=400003=403=13.33kNm2

Therefore the pressure exerted by the boy is 13.33kNm2or 13.33kPa.

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