Calculate the pressure exerted on the floor by a boy standing on both feet if the weight
of the boy is 40000 N. The area of contact of each shoe is 6 cmX25cm.
Answers
Answer:
5000000000 I s the answer of this question
Answer:
13.33kNm2or 13.33kPa.
Explanation:
For the given question we can use the formula, F=mg where F is the gravitational force, m is the mass of the body and g is the acceleration due to gravity.
We know that, P=FA where P is the pressure exerted by a body, F is the force acting on the body and A is the area where the force acts.
We are given that a boy is standing on both feet on the floor. The weight of the boy is 40kg and the area of contact of each shoe is 6 cm by 25 cm .
We know that 1kgwt=10N
Hence, 40kg wt can be converted to 40×10=400N
The area of contact of each shoe=6cm×25cm=(6100×25100)m2=151000m2
Hence, total area of contact is (151000×2)m2=3100m2
We know that
P=FA
⇒P=4003/100=400003=403=13.33kNm2
Therefore the pressure exerted by the boy is 13.33kNm2or 13.33kPa.