Calculate the pressure exerted on the floor by a boy standing on both feet if the weight of the boy is 40kg.(Assume that the area of contact of each shoe is 6 cm by 25 cm.)
1kg wt =10 n
Answers
Given : a boy standing on both feet weight of the boy is 40kg.
area of contact of each shoe is 6 cm by 25 cm
1kg wt =10 N
To Find : pressure exerted on the floor by boy
Solution :
1kg wt =10 N
=> 40kg.wt =40 * 10 = 400 N
area of contact of each shoe = 6cm x 25 cm
= (6/100) m x (25/100) m
= 15/1000 m²
There are two shoes so total area
= 2 * 15/1000 m²
= 30 /1000 m²
= 3/100 m²
Pressure = Force / Area
=> Pressure = 400 / ( 3/100)
=> Pressure = 40000 /3 N/m² or Pa
=> Pressure = 40/3 kN/m² or kPa
=> Pressure = 13.33 kN/m² or kPa
pressure exerted on the floor by boy = 13.33 kN/m² or kPa
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Answer:
13.33kn/m2
Explanation:
a boy standing on both feet wright of the boy is 40kg
area of contact of each shoe is 6cm by 25cm
1kg wt=10N
to find the pressure exerted on the floor is
solution=
1kg=10N
=40kg weight=40*10=400N
area of contact of each shoe=6cm*25m
=6/100m2*25/100m2
=15/1000m2
area are toe shoes so
2*15/1000m2
=30/1000m2
=3/100m2
pressure=force/area
pressure=400/3*100
=40000/3 n/m2
pressure=40/3Nm2
pressure exerted on the floor by boy=13.33kn/m2.
May be it's useful!!