Question

Calculate the pressure exerted on the floor by a boy standing on both feet if the weight of the boy is 40Kg. (Assume that the area of the contact of each shoe is 6 cm by 25 cm.) 1kg weight = 10N
(Class 8)​

Answer 1

Answer:

Given that the boy standing on both feet on the floor.

The weight of the boy is 40kg and the area of contact of each shoe is 6 cm by 25 cm .

We know that 1kgwt=10N

Therefore,

40kg weight can be converted to

$\sf{40 \times 10 = 400newton}$

Let's find the Area of the contact of each shoe =

$\sf{6cm \times 25cm = ( \frac{6}{100} \times \frac{25}{100}) {m}^{2} }$

$\sf \red{ = \frac{15}{1000} {m}^{2} }$

We also know that,

P = F/A

$\sf{ \implies \: P = \frac{400}{3 /100} = \frac{40000}{3} = \frac{40}{3} }$

$\sf \pink{ = 13.33kN {m}^{2} }$

Hence,

The pressure exerted on the floor by a boy standing is 13.33 kNm²/ Pa .

Answer 2

Answer:

the pressure exerted by the boy is 13.33kNm2or 13.33kPa

Explanation:

We are given that a boy is standing on both feet on the floor. The weight of the boy is 40kg and the area of contact of each shoe is 6 cm by 25 cm . Therefore the pressure exerted by the boy is 13.33kNm2or 13.33kPa.