Question

calculate the pressure exertered by 1.82 mole of the gas in a steel, vessel of volume 5.43dmsquare at 69.5c assuming ideal gas behaviour​

Answer 1

Answer:

94.25atm

Explanation:

given n=1.82

v=5.43dm³

T=69.5+273=342.5K

WKT

PV=nRT

P=nRT/V

P=1.82mol×0.821dm³atm mol⁻¹K⁻¹×342.5K/5.43dm³

P=94.25 atm