Question

Calculate the pressure extended on a surface of 0.5 m^2 by a thrust of 100kgf​

Answer 1

Answer:

Therefore, the pressure exerted on a surface of 0.5 m^2 by a thrust of 100 kgf is 200 Pascals.

Answer 2

Answer:

The pressure extended on a surface of 0.5 cm² by a thrust of 100 kgf is 2000 Pa.

Explanation:

Given:

Force exerted/thrust = 100 kgf = 100 × 10 N = 1000 N.

Area = 0.5 m²

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To find:

Pressure.

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Solution:

We know that,

Pressure = Force/Area

By substituting the values, we get

Pressure (P) = 1000/0.5 = 2000 Pa

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∴ Required pressure = 2000 Pa