Question

Calculate the pressure extended on a surface of 0.5 m^2 by a thrust of 100kgf​

Answer 1

Answer:

The pressure extended on a surface of 0.5 cm² by a thrust of 100 kgf is 2000 Pa.

Explanation:

Given:

• Force exerted/thrust = 100 kgf = 100 × 10 N = 1000 N.
• Area = 0.5 m²

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To find:

Pressure.

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Solution:

We know that,

Pressure = Force/Area

By substituting the values, we get

Pressure (P) = 1000/0.5 = 2000 Pa

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∴ Required pressure = 2000 Pa

Answer 2

100kgf = 100 kg × 9.8 m/s² = 980 N

Area of the surface = 0.5 m²

We know,

Pressure = Thrust ÷ Area,

⇒P = 980 N ÷ 0.5 m²

⇒P = 1960 N/m² = 1960 Pa {Pascal}