Question

Calculate the pressure of a gas,when its volume is 250 ml initially,the gas is expanded to a volume of 1000ml and the pressure of 304 cm of mercury.The temperature during the reaction remains constant

Answer 1

Answer:

P=n(RTV)=n×const. pls mark as brainisist

Answer 2

1.6 atm ≅1216 cm³Hg

Explanation:

P₁ = ?, P₂ = 304 cm³Hg = 304/760 = 0.4 atm, V₁ = 250 ml = 0.25 L, V₂ = 1 L

We know that at constant T,

P₁V₁ = P₂V₂

P₁ = P₂V₂/V₁

    = 0.4 × 1/0.25

    = 1.6 atm × 760 = 1216 cmHg