Question

Calculate the pressure of water at the bottom of a well if the depth of water is 10m.
(gravity=9.8 m/s² )
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Answer 1

Answer:

Answer: For under water pressure is define by this equation,P = density of water * gravitational acceleration * height under water.So for water density is equal to 1000kg/m^3. ... Then we put this values in this equation then, P = 1000*9.81*10.33. Then we get P = 101325 Pa(Pascal).

Answer 2

Answer:

the pressure at the bottom of the well is 98,000 pascals.

Explanation:

• the depth of the water in the well is 10 m
• the volume of water directly above an area A of 'a' square metres (m²) at the bottom of the well => 10×a m³.
• the density of the water is 1,000 kg/m³
• the mass of water directly above area A is                                                  (1,000 kg/m³) × (10×a m³) = (1000×10×a kg) = 10,000×a kg.
• g = 9.8 m/s², the force of gravity acting on the water directly above area A is (9.8 m/s²) × (10,000×a kg) = 9.8×10,000×a N (newtons) = 98,000×a N.
• the pressure of water acting on area A is (98,000×a N)/(a m²) = (98,000×a)/a N/m² = 98,000 pascals (pa).