World Languages, asked by yashganatra2009, 11 months ago

Calculate the pressure on the bottom of a
swimming pool 2.5 m deep. How does the pressure
compare with atmospheric pressure, 10 raised to 5 Pa?
(Density of water = 1000 kg/m)​

Answers

Answered by balagaanuradha
0

Explanation:

Strategy. We begin by solving the equation P = hρg for depth h: h=Pρg h = P ρ g . Then we take P to be 1.00 atm and ρ to be the density of the water that creates the pressure.

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