Question

Calculate the probabilities for the following statements as per the given scenario and draw the probability tree diagram also (Note: This diagram can be prepared in MS-Paint or manually).
A study undertaken by the Rajan Supervisor of Elections in 2002 revealed that 44% of registered voters are ‘Dharwadi Yuth’, 37% are Rajmoti, and 19% are others. If two registered voters are selected at random, what is the probability that both of them have the same party affiliation?

Answer 1

Answer:

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Answer 2

0.3666 is the probability that both of them will have the same party affiliation.

Given that:

44% registered voters are Dharwadi Youth

37% are Rajmoti

19% are "Others"

Therefore, Probability of selecting a:

Dharwadi youth = P(1) = 0.44

Rajmoti = P(2) = 0.37

Others= P(3) = 0.19

Now, probability of selecting two voters, and two of them having same affiliation is:

P(Both Dharwadi)+ P(Both Rajmoti)+ P(Both Others)

= [P(1)×P(1)] + [P(2)×P(2)] + [P(3)×P(3)]

= [0.44×0.44] + [0.37×0.37] + [0.19×0.19]

= 0.1936+0.1369+0.0361

= 0.3666