Calculate the probability of getting a zygote with genotype AaBbCc if a cross is made between the AABBcc and AaBbcc
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Jibo Ke Liye Janan Kyo Aniwary Hai
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There will be no zygote with the genotype which is given above.
Explanation:
- This is because there is no dominant of C present in either of the parent. There is no probability to form a gamut with that allele. As a result of this there will be formation of recessive character in all of the offspring due to the present situation in the parent.
- Hence the given genotype will be present in none of the offspring. This is in accordance to mendel's law of independent assortment
To know more,
mendel's law of inheritance - Brainly.in
https://brainly.in/question/55316
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