Question

calculate the product of uncertainty in position and velocity of an electron (m =9.1×10^-31kg, h= 6.625×10^-34,π=3.14,∆v=? , ∆x=?)​

Answer 1

Answer:

Think think you will get it don't try to copy a solution try to solve it on your own....

Answer 2

Answer:

According to Heisenberg's uncertainty principle,

∆x.m∆v = h/4π

so, ∆x.∆v = h/4πm

Hence, product of uncertainty in position and velocity = h/4πm

Here, m = 9.1 × 10⁻³¹ kg , h = 6.626 × 10⁻³⁴ J.s

Now, product of uncertainty in position and velocity = 6.626 × 10⁻³⁴/(4 × 3.14 × 9.1 × 10⁻³¹ )

= 6.626 × 10⁻³/(4 × 3.14 × 9.1)

= 0.0579 × 10⁻³ m²/s

= 5.79 × 10⁻⁵ m²/s