Question

Calculate the Q-values of the following fusion reactions
(a) H21+H21→H31+H11
(b) H21+H21→He32+n
(c) H21+H31→He42+n.
Atomic masses are
m(H21)=2.014102u,m(H31)=3.016049u,m(H32e)=3.016029u,m(H42e)=4.002603u.

Answer 1

Explanation:

a h21+h31+hsr-hu2+h11

Answer 2

The Q-values are 4.05 MeV, 3.25 MeV and 17.57 MeV, respectively.

Explanation:

• (a) $Q = 2 × m H12 - mH33 + mH13c2 = (4.028204-4.023874) × 931 MeV = 4.05 MeV$

• (b) $Q = 2 × m H12 - (m H23 + mn) c2 = [4.028204-4.024694) × 931 = 3.25 MeV.$

• (c) $Q = m H12 + m H13 - m He14 - mnc2 = (2.014102 + 3.016049 - 4.002603 - 1.008665) × 931 =17.57 MeV$