Question

calculate the quantity of carbon dioxide obtained during the decomposition of 500gm of calcuim carbonate

Answer 1

Given:

Decomposition of calcium carbonate

Mass of given calcium carbonate = 500 g

To find:

Mass of carbon dioxide formed.

Solution:

When Calcium carbonate decomposed then calcium oxide and carbon dioxide is obtained as product. The required balanced chemical reaction is-

        CaCO₃   →  CaO(s)  +  CO₂(g)

that means,

1 mole of calcium carbonate gives CO₂ = 1 mole

and molecular mass of calcium carbonate = 40 + 12 + (3×16)

                                                                      = 100 gmol⁻¹

so, moles of calcium carbonate we be calculate as-

     $moles = \frac{given mass }{molecular mass}$

    $moles = \frac{500}{100}$

therefore, moles of calcium carbonate = 5 moles

According to stoichiometry,

1 mole of CaCO₃ gives = 1 mole of CO₂ gas

5 mole of CaCO₃ gives = 1 × 5 moles of CO₂ gas

                                       = 5 moles

So, moles of carbon dioxide = 5 moles

molecular mass of carbon dioxide = 12 + (2×16)

                                                          = 44 gmol⁻¹

Therefore, mass of CO₂ formed will be calculated as-

            $moles = \frac{given mass}{molecular mass}$

          given mass = moles × molecular mass

           given mass = 5 × 44

           given mass = 220g

So, Mass of carbon dioxide obtained is 220g.