Question

Calculate the quantity of electricity that would be required to reduce 12. 3 g of nitrobenzene to aniline . If current efficiency for the process is 50 %

Answer 1

the correct answer is 115800C

Answer 2

Answer: 115800C

Explanation:

$C_6H_5NO_2+6H^++6e^{-1}\rightarrow C_6H_5NH_2+2H_2O$

1 mole of electrons carry 96500C of charge. Thus 6 mole of electrons carry=$96500\times 6=579000C$

Molar mass of nitrobenzene = 123 g

579000C of electricity is required to reduce 123 g of nitrobenzene.

Thus if  123 g of nitrobenzene is reduced to aniline by 579000C.

12.3 g of nitrobenzene is reduced to aniline by=$\frac{579000C}{123g}\times 12.3g=57900C$

But as the current efficiency is 50%, the quantity of electricity required would be $=\frac{57900}{50}\times 100=115800C$

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