Question

Calculate the quantity of metal sheet that would
be required to make 51 cylindrical cans with
a diameter of 8.4 cm and a height of 84 cm​

Answer 1

Answer:

Diameter of cylinder =8.4m

Radius =4.2 m

Height =5.4 m

Total surface area of cylinder =2πr(r+h)=253.44m

2

Wasted metal sheet =

15

1

×253.44=16.896m

Total metal sheet required =253.44+16.896=270 m

Answer 2

Answer:

Thanks for your question...

Your required answer :

• Total surface area of cylinder =
• 2 π r ( r + h )

Given ,

• Radius =
• $\frac{8.4}{2}$
• 4.2 cm

• Height =
• 84 cm

Now T . S . A . ,

• $2 \times \frac{22}{7} \times \frac{42}{10} (4.2 + 84)$
• $2 \times \frac{22}{7} \times \frac{42}{10} \times \frac{882}{10}$
• $\frac{132 \times 882}{50}$
• $\frac{116424}{50}$
• $2,328.48 \: cm {}^{2}$

Now , to find the the quantity of metal sheet that would be required to make 51 cylindrical cans multiply the TSA of cylinder with 51 :

• 2,328.48 × 51
• 118,752.48 cm of metal sheet is required to make 51 cylinder

Brainliest Please