Question

Calculate the r.m.s. velocity of air molecules at S.T.P. Given density of air at S.T.P. is 1.296 kg m^(-3).

Answer 1

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Answer 2

Solution:

let, V rms be the rms velocity of air molecules at S.T.P.

P be the pressure of air molecules at S.T.P.

p be the density of air molecules at S.T.P.

v be the volume of air molecules at S.T.P.

T be the temperature of air molecules at S.T.P.

M be the mass of air molecules at S.T.P.

R be the universal gas constant of air molecules at S.T.P.

given, p = 1.296kg m^-3

now, we know that

V rms = √3RT/M

V rms = √3P/p   since , P v= R p T   and p= M/v

V rms = √3*1/ 1.296     since, P = 1 atm at S.T.P.

V rms = √2.314 m/s.