Question

Calculate the r.m.s velocity of oxygen at a temperatur
oxygen at a temperature of 100 °C.

(Molar mass of oxygen = 32 g and R = 8.31 J mole-1 K-1)​

Answer 1

Given,

$\sf{T = 100°C = 373 K}\\\\\\\sf{M=32\ g=32\times 10^{-3}\ kg}\\\\\\\sf{R=8.31\ J\ K^{-1}\ mol^{-1}}$

We have the rms velocity,

$\sf{u=\sqrt {\dfrac {3RT}{M}}}$

Then,

$\sf{u=\sqrt{\dfrac {3\times8.31\times373}{32\times 10^{-3}}}}\\\\\\\underline {\underline {\sf{u=539.06\ ms^{-1}}}}$