Question

calculate the radius and energy of the 3rd shell of Li2+ ion​

Answer 1

Answer

1.5K answers

220.8K people helped

(i) The radius of the third orbit would be

= 0.529 × n²/Z °A

= 0.529 × 9/ 3 °A

= 1.587 °A

(ii) Energy of the electron = -13.6·Z²/n² eV

= -13.6(3)²/(3)²

= -13.6 eV

= 21.72 × 10^-19 J

Explanation:

mark me as a brainlist ,....................

and also follow me bro,.......