Question

calculate the radius of bohr's 3rd orbit in Li+2 ion

Answer 1

$\huge\underbrace\pink {\dag Final \: Answer:- \dag}$

$1.587 \AA$

$\huge\underbrace\red{\dag To \: Find:-\dag}$

radius of Bohr's 3rd orbit in $Li^{+2}$ ion

$\huge\underbrace\blue{\dag Formula Used:-\dag}$

$R_n =\frac{n^{2}}{z} \times 0.529 \AA$

$\huge\underbrace\green{\dag Things \: to \:know:-\dag}$

$R_n$ = radius

n= number of orbit  

z= atomic number  

$\huge\underbrace\blue{\dag ATQ:-\dag}$

$z=3\\n=3\\\AA = 10^{-10}$

$\huge\underbrace\pink{\dag Solution:- \dag}$

the radius of $Li^{+2}$ ion ⇒

$R_L_i=\frac{n^{2}}{z} \times 0.529 \times\AA$

$R_L_i=\frac{3^{2}}{3} \times 0.529 \times 10^{-10}$

$R_L_i=3 \times 0.529 \times 10^{-10}$

or

$R_L_i=1.587 \times 10^{-10}$

hence radius of Bohr's 3rd orbit in $Li^{+2}$ ion is $\boxed{1.587 \AA}$