Calculate the radius of curvature of an equi concave lens of refractive index 1.5 , when it is kept in a medium of refract
ive index 1.4 to have a power of -50
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Answer:
Focus of a lens is given by:
1/f= (n-1) (1/R1- 1/R2)
where f is the focal length of the lens and R1 and R2 are the radius of the refracting surface on the side of the object and on the other side respectively.
Explanation:
Let the radius be R.
R1= -R and R2= R
Power of the lens, P=50 D= 50 m-1
Refractive index, n=1.5/1.4 (first medium/ second medium)
We know that,
P= 1/f= (n-1) (1/R1- 1/R2)
By putting the values of P and n,we will get the value of R.
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