Question

calculate the radius of gyration of a hoop of radius 5.00 cm rotating about an axis passing through its center and normal on its plane​

Answer 1

Answer:

Explanation:

the radius of gyration of a hoop √35 cm

The radius of gyration of a hoop of radius  5.00 cm rotating about an axis passing through its centre and normal to its plane.

I(tangent) = 2/5 Ma² + MR²

∴  I(tangent) = 7/5 MR²

∴ Mk² = 7/5 MR²

∴ k = √(7/5 x 5² = √35 cm

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Answer 2

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$x \times radius{1 = 500mass}then \: 5.00 \times 500mass \: = {answer}$