Calculate the radius ratio of rNa+ 0.95 A0 and rcl- 1.81A0
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Answer:
Given, radius of Na+
(r +)=95 pm
Radius of Cl−
(r - )=181 pm
We know that,
Radius ratio= Radius of anion (r − )
Radius of cation (r+)
=181
95=0.523
This value lies between 0.414–0.732 range, so the coordination number of Na will be 6 as predicted by radius ratio rule.
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