Question

calculate the radius ratio of second orbit of hydrogen atom and third orbit of he+ ion​

Answer 1

Answer:

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Answer 2

Concept Introduction:-

A ratio in mathematics denotes the numeral of times a number contains another.

Given Information:-

We have been given that he$+$ ion​

To Find:-

We have to find that calculate the radius ratio of second orbit of hydrogen atom and third orbit of he$+$ ion​

Solution:-

According to the problem

We know that

radius of orbit $=\mathrm{r}=\frac{\mathrm{n}^{2} \mathrm{~h}^{2}}{4 \pi^{2} \mathrm{me}^{2}} \times \frac{1}{\mathrm{z}}=0.529 \frac{\mathrm{n}^{2}}{\mathrm{z}} \mathrm{A}$

so, ratio of $3^{\text {rd }}$ and $2^{\text {nd }}$ orbit of $\mathrm{He}^{+}$ion is

$\frac{r_{1}}{r_{2}}=\frac{n_{1}^{2}}{\mathrm{zn}_{2}^{2}} \times \mathrm{z} \Rightarrow\left(\frac{3}{2}\right)^{2}=\frac{9}{4}$

Final Answer:-

the radius ratio of second orbit of hydrogen atom and third orbit of he$+$ion​ is $\frac{9}{4}$.

#SPJ2