Calculate the range,average deviation,variance,standard deviation, of the following set of observation 3,4,5,5,6,7,7,7,8,8
Answers
Step-by-step explanation:
Given = 3,4,5,5,6,7,7,7,8,8
Range(R) = Highest value(H) - lowest value(L)
R = 8 - 3
R = 5
Average deviation = 1/n∑|x-Mean|
here, n = total number of observation
x = set of observation
x |x-Mean| Deviation x-assumed mean (A) A²
3 3 -4 16
4 2 -3 9
5 1 -2 4
5 1 -2 4
6 0 -1 1
7 1 assumed mean = 7 0 0
7 1 0 0
7 1 0 0
8 2 1 1
8 2 1 1
60 14 36
Mean = ∑x/n
= 60/10
= 6
Average deviation = (1/10)14
= 1.4
Variance = A²/(n-1)
= 36/(10-1)
= 4
Standard Variance = √variance
= √4
= 2
Answer:
The range, average deviation, variance, and standard deviation of the given set of observations are 5, 2.33, 2.6, and 1.61 respectively.
Step-by-step explanation:
Range:
The range is the difference between the largest value and the smallest value of a given set of data.
Range = Max. value - Min. value
Range = 8 - 3 = 5.
Therefore, the range of the given data set is 5.
Average Deviation:
Average deviation gives the measure of the dispersion from a central value.
It is calculated as the average of the differences between each value and the mean value.
Σ
Substituting the values, we get
Therefore, the average deviation of the given data is 2.33
Variance:
Variance gives the measure of the variability of the observations. It tells us how far the data is spread out.
Σ / n -1, where n is the number of observations in the data set.
Substituting the values, we get
Therefore, the variance of the given data is 2.6
Standard Deviation:
Standard deviation gives the measure of how dispersed the data is relative to the mean value. It is simply given as the square root of the variance.
σ =
σ =
σ = 1.61
Therefore, the standard deviation of the given data is 1.61
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