Question

calculate the range of frequencies of visible light from 3800-7600A.

Answer 1

Given

λ1=3800

λ2=7600A.

To find :

V=?

Solution :

We know that

$V=\frac{C}{\lambda }$

For the value λ1

$V=\frac{C}{\lambda1}$

Putting the value of c and λ1 we get

$V=\frac{3*10^{8}m/s }{3800*10^{-10} }$

$V=7.89 * 10^{14}s^{-1}$

For the value λ2

$V=\frac{C}{\lambda2}$

Putting the value of c and λ2 we get

$V=\frac{3*10^{8}m/s }{7600*10^{-10} }$

$V=3.75 * 10^{14} S^{-1}$