Question

Calculate the range of frequencies of visible light from 3800-7600A.

Answer 1

Frequency=speed of light÷wavelength given
Now,first 3800A
F=3×10^8m/s÷3800×10^-10
F=7.88×10^14 Hz
for 7600 A do it on u r own

Answer 2

Answer : The range of frequencies of visible light from $3800-7600A^o$ will be, $7.89\times 10^{14}s^{-1}\text{ to }3.95\times 10^{14}s^{-1}$

Explanation : Given,

Wavelength range of visible light = $3800-7600A^o$

Formula used :

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of light

$\lambda$ = wavelength of light

c = speed of light = $3\times 10^8m/s$

Now we have to calculate the frequency of $3800A^o$ wavelength of light.

$\nu=\frac{3\times 10^8m/s}{3800\times 10^{-10}m}=7.89\times 10^{14}s^{-1}$

conversion factor used : $1A^o=10^{-10}m$

Now we have to calculate the frequency of $7600A^o$ wavelength of light.

$\nu=\frac{3\times 10^8m/s}{7600\times 10^{-10}m}=3.95\times 10^{14}s^{-1}$

Therefore, the range of frequencies of visible light from $3800-7600A^o$ will be, $7.89\times 10^{14}s^{-1}\text{ to }3.95\times 10^{14}s^{-1}$