Calculate the rate constant for a first order reaction which is 40% completed in 50 minutes.
Answers
Answered by
2
Answer:
157.58 min
Explanation:
1. For the first order reaction k Assume,
a = 100 %, x = 40%, t = 50 minutes
Therefore, a – x = 100 – 40 = 60 k = (2.303/50) log (100/60) k = 0.010216 min-1
Hence,the value of the rate constant is 0.010216 min-1 2. t = ?, when x = 8O%
Therefore, a – x = 100 – 80 = 20
From above, k = 0.0102 16 min-1
t = (2.303 / 0.010216) log (100 / 20)
t = 157.58 min
The time at which the reaction will be 80% complete is 157.58 min.
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Answered by
2
Answer:
157.58 minute
Explanation:
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