Question

Calculate the rate constant for a first order reaction which is 40% completed in 50 minutes.​

Answer 1

Answer:

157.58 min

Explanation:

1. For the first order reaction k Assume,

a = 100 %, x = 40%, t = 50 minutes

Therefore, a – x = 100 – 40 = 60 k = (2.303/50) log (100/60) k = 0.010216 min-1

Hence,the value of the rate constant is 0.010216 min-1 2. t = ?, when x = 8O%

Therefore, a – x = 100 – 80 = 20

From above, k = 0.0102 16 min-1

t = (2.303 / 0.010216) log (100 / 20)

t = 157.58 min

The time at which the reaction will be 80% complete is 157.58 min.

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Hope it helps

Answer 2

Answer:

157.58 minute

Explanation:

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