calculate the rate of the reaction A +2B _> 2C + D
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Answer:
A + 2B ⇌ 2C + D
At t=0 α
2
3
α 0 0
At eq. α−x
2
3
α−x 2x x
Given, [A]=[C]
a−x=2x
∴x=
3
a
Now, K
c
=
[A][B]
2
[C]
2
[D]
=
(a−
3
a
)(
2
3a
−
3
2a
)
2
(
3
2a
)
2
×
3
a
=0.32
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