Science, asked by keshav249, 1 year ago

calculate the ratio between the kinetic energy and the potential energy of an oscillating object for the moment when t= T/12 ?

Answers

Answered by karu072004
0
ratio between the kinetic energy and potential energy is 3:1 when t=T/12
Answered by Arslankincsem
7

3:1. Given that the displacement at t=T/12, we can say x= A Sin wt = A Sin (360/T X T/12) = A/2.


Again. we know that v = Aw Cos wt - Aw Cos (360/T T/12) = Aw root under 3/2.


Therefore, Total Energy = 1/2 X m X A square X w square.


The Kinetic Energy = 1/2 X m X A square X w square 3/4.


Hence Potential Energy = Total Energy - Kinetic Energy = 1/8 X m X A square X w square.


So, Kinetic Energy / Potential Energy = 3/1.

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