calculate the ratio between the kinetic energy and the potential energy of an oscillating object for the moment when t= T/12 ?
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ratio between the kinetic energy and potential energy is 3:1 when t=T/12
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3:1. Given that the displacement at t=T/12, we can say x= A Sin wt = A Sin (360/T X T/12) = A/2.
Again. we know that v = Aw Cos wt - Aw Cos (360/T T/12) = Aw root under 3/2.
Therefore, Total Energy = 1/2 X m X A square X w square.
The Kinetic Energy = 1/2 X m X A square X w square 3/4.
Hence Potential Energy = Total Energy - Kinetic Energy = 1/8 X m X A square X w square.
So, Kinetic Energy / Potential Energy = 3/1.
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