Question

calculate the ratio mean square speed of molecules of a gas 30k and 120k
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Answer 1

Given: molecules of a gas 30k and 120k

To find: the ratio mean square speed of molecules of a gas 30k and 120k

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Solution:

• Now we know that:

v(rms) = √3RT/M

• Let v1 and v1 be mean square speed of molecules of a gas 30k and 120k .

• Then:

                 v1 / v2 = √3RT/M  / √3RT/M

• Cancelling the common terms, we get:

                 v1 / v2 = √T1 / √T2

• Now putting the value of T, we get:

                 v1 / v2 = √30 / √120

                  v1 / v2 = 1/√4

                 v1 / v2 = 1/2

Answer:

            So the ratio of mean square speed of molecules of a gas 30k and 120k  is 1/2.

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Answer 2

Answer:

Given: Temperature ( T1) : 30 K

(T2) : 120 K

To find: Ratio of mean square

Formula: Vrms= √ 3RT

M

Solution:

V1 = √3RT1 × √ M

V2. M. 3RT2

V1 = √ T1

V2. T2

Squaring on both the sides, we get

V1²= T1

V2² T2

V1²= 30

V2² 120

V1²= 1

V2² 4

therefore, Ratio of mean square is 1/4