calculate the ratio of atoms present bin 5g of magnesium and 5g of iron (atomic mass of mg- 25u, fe- 56u)
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Answer:
Explanation:
No of atoms=No. of moles × atomicity × N(6.02×10^23)
No. of Mg atoms = (5/24)×1×N
No. of Fe atoms= (5/56)×1×N
ratio(Mg:Fe)= (5/24)×1×N/ (5/56)×1×N
=7/3
hence answer is 7:3
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