Question

calculate the ratio of atoms present in 5 gram of magnesium and 5 gram of iron​

Answer 1

Explanation:

the weight of the magnesium is 4gram and atomic mass is 24 so number of atom =no.of.moles * avogadro number.

similar for iron so it is ratio is 4/24 * 56/4.

Answer 2

Explanation:

The ratio of atoms present in 5g of magnesium and 5g of iron is \frac{7}{3}37<br>

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Explanation:<br>

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According to avogadro&apos;s law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro&apos;s number 6.023\times 10^{23}6.023×1023 of particles.<br>

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To calculate the number of moles, we use the equation:<br>

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}Number of moles=Molar massGiven mass<br>

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a) \text{Number of moles of magnesium}=\frac{5g}{24g/mol}Number of moles of magnesium=24g/mol5g<br>

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1 mole of magnesium contains = 6.023\times 10^{23}6.023×1023 atoms<br>

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Thus \frac{5g}{24g/mol}24g/mol5g moles of magnesium contains = \frac{6.023\times 10^{23}}{1}\times \frac{5g}{24g/mol}16.023×1023×24g/mol5g atoms<br>

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b) \text{Number of moles of iron}=\frac{5g}{56g/mol}Number of moles of iron=56g/mol5g<br>

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1 mole of iron contains = 6.023\times 10^{23}6.023×1023 atoms<br>

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Thus \frac{5g}{56g/mol}56g/mol5g moles of iron contains = \frac{6.023\times 10^{23}}{1}\times \frac{5g}{56g/mol}16.023×1023×56g/mol5g atoms<br>

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Ratio of of atoms present in 5g of magnesium and 5g of iron =\frac{\frac{5}{24}}{\frac{5}{56}}=\frac{7}{3}565245=37<br>

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