Question

Calculate the ratio of average kinetic energy of one molecule of diatomic rigid

Answer 1

your question is ----> Calculate the ratio of average kinetic energy of one molecule of diatomic (rigid) and diatomic (elastic) at temperature 150 degree Celsius ?

average kinetic energy of one molecule of diatomic (rigid) = 5/2kT , where k is Boltzmann constant and T is temperature.
[ here we know, degree of freedom of rigid diatomic molecule is 5 ]

average kinetic energy of one molecule of diatomic (elastic) = 7/2 kT
[here, we know, degree of freedom of elastic diatomic molecule is 7]

now, ratio of average kinetic energy = (5/2kT)/(7/2kT)
= 5/7

Answer 2

just see the uploaded photo......this solution is from me but from some other source ....bt it is correct.....i hope it will help u in the same manner it helped it