Calculate the ratio of displacement to amplitude when kinetic energy of a body is three times its potential energy
Answers
Answered by
0
Answer:
Correct option is
B
±
5
1
Explanation:
KE
=4
KE+PE=
2
1
mω
2
A
2
⇒KE(1+
4
1
)=
2
1
mω
2
A
2
⇒KE=
5
2
mω
2
A
2
=
2
1
mω
2
(A
2
−x
2
)
⇒x
2
=A
2
(1−
5
4
)=
5
A
2
⇒
A
x
=±
5
1
Similar questions